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TBDY 2018 story force distribution
Distributes the base shear VtE over the stories per §4.7.2, including the additional top-story force ΔFNE = 0.0075·N·VtE.
Inputs
| Story | wi (mass/weight) | Hi [m] | wi·Hi | Fi [kN] |
|---|
ΔFNE = — kN · Σ(wi·Hi) = —Σ Fi = — kN (= VtE)
Citations
§4.7.2.2ΔFNE = 0.0075·N·VtE, added at the top story (Denk. 4.22).
§4.7.2.3FiE = (VtE−ΔFNE)·(wi·Hi)/Σ(wj·Hj) (Denk. 4.23).
VERIFYReproduces a published worked example (VtE=28.31, 4 stories → F4=9.83, F3=9.24, F2=6.15, F1=3.09; Σ=28.31).
Preliminary calculation tool. Results are for preliminary sizing and cross-check only. Final design, sealed responsibility, and permit submissions require the full official text of the referenced regulations and the review of a licensed engineer.